MySql：按多个条件获取递增项目的计数

Here is the dummy data,这是一个呼叫记录数据表.
这是它的一瞥：

|  call_id  |   customer   |   company   |     call_start      | 
|-----------|--------------|-------------|---------------------|
|1411482360 | 001143792042 | 08444599175 | 2014-07-31 13:55:03 |
|1476992122 | 001143792042 | 08441713191 | 2014-07-31 14:05:10 |

客户和公司字段代表他们的电话号码.

>要求是根据以下逻辑计算总“增益”和总“丢失”值：

编辑：

– 客户A致电公司A.
– 如果客户A致电B公司,那么B公司将获得1个收益,而A公司将有1个收益.
? – 如果客户A致电公司C,则公司C将获得1个收益,而公司B将收取1个损失.
– 如果客户A再次致电公司C,则溢出/收益不会受到影响.
– 一旦客户A第二次拨打电话,收益/损失才会发挥作用.
? – 如果客户按此顺序呼叫公司：A,B,C,A,D,则流程应如下所示：

A ->  
B ->  B +1 gain,A +1 lost
B ->  
C ->  C +1 gain,B +1 lost
A ->  A +1 gain,C +1 lost
A ->  
C ->  C +1 gain,A +1 lost
B ->  B +1 gain,C +1 lost
D ->  D +1 gain,B +1 lost

经过上述过程后,我们应该将总值设为：

Company    Total gain    Total lost
  A            1             2            
  B            2             2       
  C            2             2         
  D            1             0     

我开始研究这个但是它错了,它只是一个想法,它不会根据上述条件给我单独增加的增益和丢失值：

DROP TABLE IF EXISTS GetTotalGainAndLost;

CREATE TEMPORARY TABLE IF NOT EXISTS GetTotalGainAndLost
    AS 
        (
        SELECT SUM(count) as 'TotalGainAndLost',`date`,DAY(`date`) as 'DAY' 
        FROM (SELECT count(*) as 'count',customer,`date` 
            FROM (SELECT customer,company,count(*) AS 'count',DATE_FORMAT(`call_end`,'%Y-%m-%d') as 'date' 
                FROM calls 
                WHERE `call_end` LIKE CONCAT(2014,'-',RIGHT(CAST(concat('0',01) AS CHAR),2),'-%')
                GROUP BY customer,DAY(`call_end`) ORDER BY `call_end` ASC)
            as tbl1 group by customer,`date` having count(*) > 1) 
        as tbl2 GROUP by `date`
        );

Select * from GetTotalGainAndLost;

DROP TABLE GetTotalGainAndLost;

此查询不显示任何结果.

>所需的输出如下所示：

每个公司和日期应该是一行(总收益和一天中的丢失电话,例如1月)

|  company    |  totalGain |  totalLost  |     date     |  DAY  | 
|-------------|------------|-------------|--------------|-------|
| 08444599175 |     17     |       6     | 2014-07-01   |  1    |
| 08444599175 |     12     |      10     | 2014-07-02   |  2    |
| 08444599175 |      3     |       6     | 2014-07-02   |  3    |
| 08444599175 |   ....     |      ...    |     ...      | ...   |
| 08444599175 |      7     |       6     | 2014-07-31   | 31    |

让我们将N表示为公司出现的次数.让我们尝试在三个简单的规则中简化公式.

>出现的第一家公司将获得N – 1收益,N亏损.
>中期公司将有N收益,N亏损.
>最后一家公司将获得N增益,N – 1损失

测试

在你的例子中：

>从公司A开始,它出现3次.
> B公司出现3次
>公司C出现2次
>以公司D结束,出现1次.

结果

Company      Gain           Lost  
  A            2             3            
  B            3             3       
  C            2             2         
  D            1             0    

转换为SQL

首先,我们首先计算每家公司的数量.

SELECT
    company,COUNT(*) AS gain,COUNT(*) AS lost,DATE(call_start) AS date
FROM calls 
GROUP BY DATE(call_start),company

然后,我们开始选择每个公司第一次出现在每个客户的号码.

SELECT company,-COUNT(*) AS gain,0 AS lost,DATE(call_start) AS `date`
FROM calls INNER JOIN (
    SELECT MIN(call_id) AS call_id FROM calls GROUP BY DATE(call_start),customer
) AS t ON (calls.call_id = t.call_id)
GROUP BY DATE(call_start),calls.company

最后出现的公司数量.

SELECT company,0 AS gain,-COUNT(*) AS lost,DATE(call_start) AS `date`
FROM calls INNER JOIN (
    SELECT MAX (call_id) AS call_id FROM calls GROUP BY DATE(call_start),calls.company

结合SQL

最后,我们可以使用UNION ALL将整个SQL组合在一起,然后再执行另一个组.

SELECT company,SUM(gain) AS gain,SUM(lost) AS lost,`date` FROM (
    (
        SELECT
            company,DATE(call_start) AS `date`
        FROM calls 
        GROUP BY DATE(call_start),company
    ) UNION ALL (
        SELECT company,DATE(call_start) AS `date`
        FROM calls INNER JOIN (
            SELECT MIN(call_id) AS call_id FROM calls GROUP BY DATE(call_start),customer
        ) AS t ON (calls.call_id = t.call_id)
        GROUP BY DATE(call_start),calls.company
    ) UNION ALL (
        SELECT company,DATE(call_start) AS `date`
        FROM calls INNER JOIN (
            SELECT MAX(call_id) AS call_id FROM calls GROUP BY DATE(call_start),calls.company
    )
) AS t
GROUP BY `date`,company

澄清

上述查询假设每个新的一天都是独立的.例如,

>客户A致电公司A(第1天)
>客户A致电公司B(第1天)B获得1,A输1
>客户A致电公司C(第1天)C获得1,B输了1
>客户A致电公司D(第2天)
>客户A呼叫公司E(第2天)E获得1,D输掉1

结果将是

COM   G     L   DAY
 ----------------
A     0     1    1
B     1     1    1
C     1     0    1
D     0     1    2
E     1     0    2

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